Base | Representation |
---|---|
bin | 1011111011000111000100… |
… | …1111001110010000000110 |
3 | 1201102022120012100102010020 |
4 | 2332301301033032100012 |
5 | 3204244031320101314 |
6 | 43514414251040010 |
7 | 2522114330235003 |
oct | 276616117162006 |
9 | 51368505312106 |
10 | 13110140003334 |
11 | 41a4a85284440 |
12 | 15789bb440006 |
13 | 74138619401a |
14 | 334769a508aa |
15 | 17b058bd6da9 |
hex | bec713ce406 |
13110140003334 has 32 divisors (see below), whose sum is σ = 28605789830016. Its totient is φ = 3972513030720.
The previous prime is 13110140003321. The next prime is 13110140003339. The reversal of 13110140003334 is 43330004101131.
13110140003334 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×131101400033342 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110140003339) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5386132 + ... + 7431735.
It is an arithmetic number, because the mean of its divisors is an integer number (893930932188).
Almost surely, 213110140003334 is an apocalyptic number.
13110140003334 is an abundant number, since it is smaller than the sum of its proper divisors (15495649826682).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110140003334 is a wasteful number, since it uses less digits than its factorization.
13110140003334 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12833380.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13110140003334 its reverse (43330004101131), we get a palindrome (56440144104465).
The spelling of 13110140003334 in words is "thirteen trillion, one hundred ten billion, one hundred forty million, three thousand, three hundred thirty-four".
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