Base | Representation |
---|---|
bin | 1011111011000111101101… |
… | …1111101110110011000000 |
3 | 1201102100000012011222121210 |
4 | 2332301323133232303000 |
5 | 3204244404344244404 |
6 | 43514443315450120 |
7 | 2522121520120416 |
oct | 276617337566300 |
9 | 51370005158553 |
10 | 13110312103104 |
11 | 41a5063440557 |
12 | 1578a48bb6940 |
13 | 7413b2a2ccc8 |
14 | 33478484d2b6 |
15 | 17b068d7e689 |
hex | bec7b7eecc0 |
13110312103104 has 28 divisors (see below), whose sum is σ = 34687700773304. Its totient is φ = 4370104034304.
The previous prime is 13110312103069. The next prime is 13110312103121. The reversal of 13110312103104 is 40130121301131.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34141437577 + ... + 34141437960.
Almost surely, 213110312103104 is an apocalyptic number.
It is an amenable number.
13110312103104 is an abundant number, since it is smaller than the sum of its proper divisors (21577388670200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110312103104 is an equidigital number, since it uses as much as digits as its factorization.
13110312103104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68282875552 (or 68282875542 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 13110312103104 its reverse (40130121301131), we get a palindrome (53240433404235).
The spelling of 13110312103104 in words is "thirteen trillion, one hundred ten billion, three hundred twelve million, one hundred three thousand, one hundred four".
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