Base | Representation |
---|---|
bin | 111101000011001011… |
… | …1100001101111010010 |
3 | 110112101211001101102020 |
4 | 1322012113201233102 |
5 | 4121444423131310 |
6 | 140121131232310 |
7 | 12320601642414 |
oct | 1720627415722 |
9 | 415354041366 |
10 | 131103333330 |
11 | 50667460862 |
12 | 214aa2a8696 |
13 | c4946517a8 |
14 | 64b9c349b4 |
15 | 3624b57170 |
hex | 1e865e1bd2 |
131103333330 has 32 divisors (see below), whose sum is σ = 314658864000. Its totient is φ = 34959681792.
The previous prime is 131103333259. The next prime is 131103333337. The reversal of 131103333330 is 33333301131.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 131103333330.
It is not an unprimeable number, because it can be changed into a prime (131103333337) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1116771 + ... + 1228569.
It is an arithmetic number, because the mean of its divisors is an integer number (9833089500).
Almost surely, 2131103333330 is an apocalyptic number.
131103333330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131103333330 is an abundant number, since it is smaller than the sum of its proper divisors (183555530670).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131103333330 is a wasteful number, since it uses less digits than its factorization.
131103333330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150898.
The product of its (nonzero) digits is 2187, while the sum is 24.
Adding to 131103333330 its reverse (33333301131), we get a palindrome (164436634461).
The spelling of 131103333330 in words is "one hundred thirty-one billion, one hundred three million, three hundred thirty-three thousand, three hundred thirty".
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