Base | Representation |
---|---|
bin | 111101000011011000… |
… | …1010101111001110001 |
3 | 110112102021210012100121 |
4 | 1322012301111321301 |
5 | 4122003141204333 |
6 | 140121532250241 |
7 | 12321013316143 |
oct | 1720661257161 |
9 | 415367705317 |
10 | 131110100593 |
11 | 5067026313a |
12 | 214b0610981 |
13 | c495b80aa4 |
14 | 64baab6c93 |
15 | 362554232d |
hex | 1e86c55e71 |
131110100593 has 2 divisors, whose sum is σ = 131110100594. Its totient is φ = 131110100592.
The previous prime is 131110100587. The next prime is 131110100689. The reversal of 131110100593 is 395001011131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 131107719744 + 2380849 = 362088^2 + 1543^2 .
It is a cyclic number.
It is not a de Polignac number, because 131110100593 - 29 = 131110100081 is a prime.
It is not a weakly prime, because it can be changed into another prime (131110100293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555050296 + 65555050297.
It is an arithmetic number, because the mean of its divisors is an integer number (65555050297).
Almost surely, 2131110100593 is an apocalyptic number.
It is an amenable number.
131110100593 is a deficient number, since it is larger than the sum of its proper divisors (1).
131110100593 is an equidigital number, since it uses as much as digits as its factorization.
131110100593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 405, while the sum is 25.
The spelling of 131110100593 in words is "one hundred thirty-one billion, one hundred ten million, one hundred thousand, five hundred ninety-three".
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