Base | Representation |
---|---|
bin | 10011000101000011110… |
… | …001011100100101010111 |
3 | 11122100011221211120200102 |
4 | 103011003301130211113 |
5 | 132440114111422022 |
6 | 2442151215204315 |
7 | 163503221432003 |
oct | 23050361344527 |
9 | 4570157746612 |
10 | 1311102060887 |
11 | 466042a29923 |
12 | 19212551669b |
13 | 96837207638 |
14 | 47659c25703 |
15 | 24188924a92 |
hex | 13143c5c957 |
1311102060887 has 2 divisors, whose sum is σ = 1311102060888. Its totient is φ = 1311102060886.
The previous prime is 1311102060883. The next prime is 1311102060943. The reversal of 1311102060887 is 7880602011131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311102060887 - 22 = 1311102060883 is a prime.
It is a super-2 number, since 2×13111020608872 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1311102060887.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311102060881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655551030443 + 655551030444.
It is an arithmetic number, because the mean of its divisors is an integer number (655551030444).
Almost surely, 21311102060887 is an apocalyptic number.
1311102060887 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311102060887 is an equidigital number, since it uses as much as digits as its factorization.
1311102060887 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 38.
The spelling of 1311102060887 in words is "one trillion, three hundred eleven billion, one hundred two million, sixty thousand, eight hundred eighty-seven".
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