1311102063133 has 2 divisors, whose sum is σ = 1311102063134. Its totient is φ = 1311102063132.

The previous prime is 1311102063091. The next prime is 1311102063137. The reversal of 1311102063133 is 3313602011131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1258071803044 + 53030260089 = 1121638^2 + 230283^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311102063133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311102063098 and 1311102063107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311102063137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655551031566 + 655551031567.

It is an arithmetic number, because the mean of its divisors is an integer number (655551031567).

Almost surely, 2^{1311102063133} is an apocalyptic number.

It is an amenable number.

1311102063133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311102063133 is an equidigital number, since it uses as much as digits as its factorization.

1311102063133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 1311102063133 its reverse (3313602011131), we get a palindrome (4624704074264).

The spelling of 1311102063133 in words is "one trillion, three hundred eleven billion, one hundred two million, sixty-three thousand, one hundred thirty-three".