Base | Representation |
---|---|
bin | 11101110011111010000000… |
… | …010100100001101010110010 |
3 | 122012020000122221112010201211 |
4 | 131303322000110201222302 |
5 | 114141102421040322010 |
6 | 1142503130202150334 |
7 | 36421260031455103 |
oct | 3563720024415262 |
9 | 565200587463654 |
10 | 131110324542130 |
11 | 3885963818a56a |
12 | 128560864b23aa |
13 | 582085c35c38b |
14 | 2453ab894a3aa |
15 | 102573166308a |
hex | 773e80521ab2 |
131110324542130 has 32 divisors (see below), whose sum is σ = 250155147052800. Its totient is φ = 49304999627520.
The previous prime is 131110324542121. The next prime is 131110324542137. The reversal of 131110324542130 is 31245423011131.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 131110324542092 and 131110324542101.
It is not an unprimeable number, because it can be changed into a prime (131110324542137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 423136680 + ... + 423446419.
It is an arithmetic number, because the mean of its divisors is an integer number (7817348345400).
Almost surely, 2131110324542130 is an apocalyptic number.
131110324542130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131110324542130 is a deficient number, since it is larger than the sum of its proper divisors (119044822510670).
131110324542130 is a wasteful number, since it uses less digits than its factorization.
131110324542130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 846584034.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 131110324542130 its reverse (31245423011131), we get a palindrome (162355747553261).
The spelling of 131110324542130 in words is "one hundred thirty-one trillion, one hundred ten billion, three hundred twenty-four million, five hundred forty-two thousand, one hundred thirty".
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