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13111100132020 = 2251159595909691
BaseRepresentation
bin1011111011001010101001…
…1101110100101010110100
31201102102001010000000001221
42332302222131310222310
53204303013113211040
643515053430000124
72522150166215002
oct276625235645264
951372033000057
1013111100132020
1141a5428245320
121579028aa6044
137414aa0810c7
1433481b37da72
1517b0b313e74a
hexbecaa774ab4

13111100132020 has 24 divisors (see below), whose sum is σ = 30036338484768. Its totient is φ = 4767672775200.

The previous prime is 13111100132017. The next prime is 13111100132023. The reversal of 13111100132020 is 2023100111131.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (13111100132017) and next prime (13111100132023).

It is a super-2 number, since 2×131111001320202 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13111100131985 and 13111100132003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111100132023) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29797954626 + ... + 29797955065.

It is an arithmetic number, because the mean of its divisors is an integer number (1251514103532).

Almost surely, 213111100132020 is an apocalyptic number.

13111100132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13111100132020 is an abundant number, since it is smaller than the sum of its proper divisors (16925238352748).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111100132020 is a wasteful number, since it uses less digits than its factorization.

13111100132020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59595909711 (or 59595909709 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 13111100132020 its reverse (2023100111131), we get a palindrome (15134200243151).

The spelling of 13111100132020 in words is "thirteen trillion, one hundred eleven billion, one hundred million, one hundred thirty-two thousand, twenty".

Divisors: 1 2 4 5 10 11 20 22 44 55 110 220 59595909691 119191819382 238383638764 297979548455 595959096910 655555006601 1191918193820 1311110013202 2622220026404 3277775033005 6555550066010 13111100132020