Base | Representation |
---|---|
bin | 10011000101000100111… |
… | …010100010001000010000 |
3 | 11122100020021212222012100 |
4 | 103011010322202020100 |
5 | 132440134013020422 |
6 | 2442153142000400 |
7 | 163503543326544 |
oct | 23050472421020 |
9 | 4570207788170 |
10 | 1311121220112 |
11 | 4660528254a0 |
12 | 19212ba16100 |
13 | 9683b185162 |
14 | 4765c5b1a24 |
15 | 2418a45b7ac |
hex | 13144ea2210 |
1311121220112 has 60 divisors (see below), whose sum is σ = 4002892820784. Its totient is φ = 397309460160.
The previous prime is 1311121220111. The next prime is 1311121220177. The reversal of 1311121220112 is 2110221211131.
It is a happy number.
1311121220112 is a `hidden beast` number, since 1 + 311 + 1 + 21 + 220 + 112 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (1311121220111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 413862438 + ... + 413865605.
Almost surely, 21311121220112 is an apocalyptic number.
1311121220112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1311121220112 is an abundant number, since it is smaller than the sum of its proper divisors (2691771600672).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311121220112 is a wasteful number, since it uses less digits than its factorization.
1311121220112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 827728068 (or 827728059 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 18.
Adding to 1311121220112 its reverse (2110221211131), we get a palindrome (3421342431243).
The spelling of 1311121220112 in words is "one trillion, three hundred eleven billion, one hundred twenty-one million, two hundred twenty thousand, one hundred twelve".
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