Base | Representation |
---|---|
bin | 10011000101000101100… |
… | …000010110010001100110 |
3 | 11122100020222112121011110 |
4 | 103011011200112101212 |
5 | 132440144032224110 |
6 | 2442154134245450 |
7 | 163504023514305 |
oct | 23050540262146 |
9 | 4570228477143 |
10 | 1311131133030 |
11 | 466058386194 |
12 | 1921331b6886 |
13 | 968402461a4 |
14 | 4765da3243c |
15 | 2418b268a20 |
hex | 13145816466 |
1311131133030 has 32 divisors (see below), whose sum is σ = 3158074720224. Its totient is φ = 348372746496.
The previous prime is 1311131133029. The next prime is 1311131133047. The reversal of 1311131133030 is 303311311131.
It is a junction number, because it is equal to n+sod(n) for n = 1311131132988 and 1311131133006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 78880447 + ... + 78897066.
It is an arithmetic number, because the mean of its divisors is an integer number (98689835007).
Almost surely, 21311131133030 is an apocalyptic number.
1311131133030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1311131133030 is an abundant number, since it is smaller than the sum of its proper divisors (1846943587194).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311131133030 is a wasteful number, since it uses less digits than its factorization.
1311131133030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157777800.
The product of its (nonzero) digits is 243, while the sum is 21.
Adding to 1311131133030 its reverse (303311311131), we get a palindrome (1614442444161).
The spelling of 1311131133030 in words is "one trillion, three hundred eleven billion, one hundred thirty-one million, one hundred thirty-three thousand, thirty".
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