13111314241432 has 64 divisors (see below), whose sum is σ = 27100116086400. Its totient is φ = 5897151421440.

The previous prime is 13111314241427. The next prime is 13111314241439. The reversal of 13111314241432 is 23414241311131.

It is a super-2 number, since 2×13111314241432² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13111314241394 and 13111314241403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111314241439) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46662819 + ... + 46942957.

It is an arithmetic number, because the mean of its divisors is an integer number (423439313850).

Almost surely, 2^{13111314241432} is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13111314241432, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13550058043200).

13111314241432 is an abundant number, since it is smaller than the sum of its proper divisors (13988801844968).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111314241432 is a wasteful number, since it uses less digits than its factorization.

13111314241432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 285736 (or 285732 counting only the distinct ones).

The product of its digits is 6912, while the sum is 31.

Adding to 13111314241432 its reverse (23414241311131), we get a palindrome (36525555552563).

The spelling of 13111314241432 in words is "thirteen trillion, one hundred eleven billion, three hundred fourteen million, two hundred forty-one thousand, four hundred thirty-two".