13111314241439 has 2 divisors, whose sum is σ = 13111314241440. Its totient is φ = 13111314241438.

The previous prime is 13111314241427. The next prime is 13111314241451. The reversal of 13111314241439 is 93414241311131.

It is a balanced prime because it is at equal distance from previous prime (13111314241427) and next prime (13111314241451).

It is a cyclic number.

It is not a de Polignac number, because 13111314241439 - 2¹⁶ = 13111314175903 is a prime.

It is a super-3 number, since 3×13111314241439³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111314241339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555657120719 + 6555657120720.

It is an arithmetic number, because the mean of its divisors is an integer number (6555657120720).

Almost surely, 2^{13111314241439} is an apocalyptic number.

13111314241439 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111314241439 is an equidigital number, since it uses as much as digits as its factorization.

13111314241439 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 38.

The spelling of 13111314241439 in words is "thirteen trillion, one hundred eleven billion, three hundred fourteen million, two hundred forty-one thousand, four hundred thirty-nine".