1311140114030 has 32 divisors (see below), whose sum is σ = 2481456846240. Its totient is φ = 498070177920.

The previous prime is 1311140114029. The next prime is 1311140114083. The reversal of 1311140114030 is 304110411131.

It is a junction number, because it is equal to n+sod(n) for n = 1311140113993 and 1311140114011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37041104 + ... + 37076483.

It is an arithmetic number, because the mean of its divisors is an integer number (77545526445).

Almost surely, 2^{1311140114030} is an apocalyptic number.

1311140114030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1311140114030 is a deficient number, since it is larger than the sum of its proper divisors (1170316732210).

1311140114030 is a wasteful number, since it uses less digits than its factorization.

1311140114030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74117684.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1311140114030 its reverse (304110411131), we get a palindrome (1615250525161).

The spelling of 1311140114030 in words is "one trillion, three hundred eleven billion, one hundred forty million, one hundred fourteen thousand, thirty".