Base | Representation |
---|---|
bin | 1011111011001011110011… |
… | …1101011010010001101110 |
3 | 1201102102211201211101001000 |
4 | 2332302330331122101232 |
5 | 3204304132030334124 |
6 | 43515144312101130 |
7 | 2522160654401262 |
oct | 276627475322156 |
9 | 51372751741030 |
10 | 13111410402414 |
11 | 41a55773a4035 |
12 | 15790b49947a6 |
13 | 74152943685c |
14 | 33484a6680a2 |
15 | 17b0d04cb6c9 |
hex | becbcf5a46e |
13111410402414 has 64 divisors (see below), whose sum is σ = 30680707737600. Its totient is φ = 4138995236544.
The previous prime is 13111410402413. The next prime is 13111410402499. The reversal of 13111410402414 is 41420401411131.
13111410402414 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 1 + 410 + 4 + 0 + 241 + 4 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111410402413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 694819 + ... + 5167745.
It is an arithmetic number, because the mean of its divisors is an integer number (479386058400).
Almost surely, 213111410402414 is an apocalyptic number.
13111410402414 is an abundant number, since it is smaller than the sum of its proper divisors (17569297335186).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111410402414 is a wasteful number, since it uses less digits than its factorization.
13111410402414 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4475814 (or 4475808 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 27.
Adding to 13111410402414 its reverse (41420401411131), we get a palindrome (54531811813545).
The spelling of 13111410402414 in words is "thirteen trillion, one hundred eleven billion, four hundred ten million, four hundred two thousand, four hundred fourteen".
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