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13111415050453 is a prime number
BaseRepresentation
bin1011111011001011110100…
…1111001001000011010101
31201102102212001120111221121
42332302331033021003111
53204304134223103303
643515144555443541
72522161042040356
oct276627517110325
951372761514847
1013111415050453
1141a5579a89195
1215790b64565b1
1374152a3a3385
1433484b117d2d
1517b0d0ae89bd
hexbecbd3c90d5

13111415050453 has 2 divisors, whose sum is σ = 13111415050454. Its totient is φ = 13111415050452.

The previous prime is 13111415050417. The next prime is 13111415050607. The reversal of 13111415050453 is 35405051411131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13093346851729 + 18068198724 = 3618473^2 + 134418^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111415050453 - 241 = 10912391794901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111415054453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555707525226 + 6555707525227.

It is an arithmetic number, because the mean of its divisors is an integer number (6555707525227).

Almost surely, 213111415050453 is an apocalyptic number.

It is an amenable number.

13111415050453 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111415050453 is an equidigital number, since it uses as much as digits as its factorization.

13111415050453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 34.

Adding to 13111415050453 its reverse (35405051411131), we get a palindrome (48516466461584).

The spelling of 13111415050453 in words is "thirteen trillion, one hundred eleven billion, four hundred fifteen million, fifty thousand, four hundred fifty-three".