Base | Representation |
---|---|
bin | 1011111011001110011111… |
… | …1110111011110100010110 |
3 | 1201102111201001001121200021 |
4 | 2332303213332323310112 |
5 | 3204312121322102410 |
6 | 43515344055135354 |
7 | 2522214600641236 |
oct | 276634776736426 |
9 | 51374631047607 |
10 | 13112132222230 |
11 | 41a5907896a38 |
12 | 157927667455a |
13 | 741612b45782 |
14 | 3348b8481cc6 |
15 | 17b123a5deda |
hex | bece7fbbd16 |
13112132222230 has 32 divisors (see below), whose sum is σ = 23760349260480. Its totient is φ = 5209634620800.
The previous prime is 13112132222207. The next prime is 13112132222281. The reversal of 13112132222230 is 3222223121131.
It is a super-2 number, since 2×131121322222302 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13112132222195 and 13112132222204.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16074592 + ... + 16870588.
It is an arithmetic number, because the mean of its divisors is an integer number (742510914390).
Almost surely, 213112132222230 is an apocalyptic number.
13112132222230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13112132222230 is a deficient number, since it is larger than the sum of its proper divisors (10648217038250).
13112132222230 is a wasteful number, since it uses less digits than its factorization.
13112132222230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 807064.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13112132222230 its reverse (3222223121131), we get a palindrome (16334355343361).
The spelling of 13112132222230 in words is "thirteen trillion, one hundred twelve billion, one hundred thirty-two million, two hundred twenty-two thousand, two hundred thirty".
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