Base | Representation |
---|---|
bin | 100111000100111… |
… | …1101000000110010 |
3 | 10101101022111020000 |
4 | 1032021331000302 |
5 | 10141133411200 |
6 | 334040130430 |
7 | 44331200652 |
oct | 11611750062 |
9 | 3341274200 |
10 | 1311232050 |
11 | 61317a057 |
12 | 307166a16 |
13 | 17b86b56b |
14 | c6206362 |
15 | 7a1ad300 |
hex | 4e27d032 |
1311232050 has 90 divisors (see below), whose sum is σ = 3649696743. Its totient is φ = 349047360.
The previous prime is 1311232037. The next prime is 1311232057. The reversal of 1311232050 is 502321131.
It can be written as a sum of positive squares in 5 ways, for example, as 97476129 + 1213755921 = 9873^2 + 34839^2 .
It is a tau number, because it is divible by the number of its divisors (90).
It is an ABA number since it can be written as A⋅BA, here for A=2, B=25605.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (1311232057) by changing a digit.
It is a polite number, since it can be written in 44 ways as a sum of consecutive naturals, for example, 2304166 + ... + 2304734.
Almost surely, 21311232050 is an apocalyptic number.
1311232050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1311232050
1311232050 is an abundant number, since it is smaller than the sum of its proper divisors (2338464693).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311232050 is an frugal number, since it uses more digits than its factorization.
1311232050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1162 (or 579 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 18.
The square root of 1311232050 is about 36210.9382645631. The cubic root of 1311232050 is about 1094.5270992304.
Multiplying 1311232050 by its sum of digits (18), we get a square (23602176900 = 1536302).
1311232050 divided by its sum of digits (18) gives a square (72846225 = 85352).
Adding to 1311232050 its reverse (502321131), we get a palindrome (1813553181).
The spelling of 1311232050 in words is "one billion, three hundred eleven million, two hundred thirty-two thousand, fifty".
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