Base | Representation |
---|---|
bin | 1011111011001111100011… |
… | …1010110011111011100100 |
3 | 1201102112102211201000012220 |
4 | 2332303320322303323210 |
5 | 3204313212041312040 |
6 | 43515432205112340 |
7 | 2522224621010634 |
oct | 276637072637344 |
9 | 51375384630186 |
10 | 13112416354020 |
11 | 41a5a432123a5 |
12 | 15793358586b0 |
13 | 7416599789a9 |
14 | 3349040c46c4 |
15 | 17b13d9862d0 |
hex | becf8eb3ee4 |
13112416354020 has 48 divisors (see below), whose sum is σ = 38874457899648. Its totient is φ = 3290959398400.
The previous prime is 13112416354019. The next prime is 13112416354031. The reversal of 13112416354020 is 2045361421131.
It is a super-2 number, since 2×131124163540202 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6427654056 + ... + 6427656095.
It is an arithmetic number, because the mean of its divisors is an integer number (809884539576).
Almost surely, 213112416354020 is an apocalyptic number.
13112416354020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13112416354020 is an abundant number, since it is smaller than the sum of its proper divisors (25762041545628).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13112416354020 is a wasteful number, since it uses less digits than its factorization.
13112416354020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12855310180 (or 12855310178 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 33.
Adding to 13112416354020 its reverse (2045361421131), we get a palindrome (15157777775151).
The spelling of 13112416354020 in words is "thirteen trillion, one hundred twelve billion, four hundred sixteen million, three hundred fifty-four thousand, twenty".
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