Base | Representation |
---|---|
bin | 1011111011001111111000… |
… | …0100010100100101011111 |
3 | 1201102112122212020112002222 |
4 | 2332303332010110211133 |
5 | 3204313401144430101 |
6 | 43515444532335555 |
7 | 2522230020143063 |
oct | 276637604244537 |
9 | 51375585215088 |
10 | 13112502733151 |
11 | 41a5a87a50308 |
12 | 157935a7745bb |
13 | 7416718307c3 |
14 | 33491176baa3 |
15 | 17b14634a01b |
hex | becfe11495f |
13112502733151 has 2 divisors, whose sum is σ = 13112502733152. Its totient is φ = 13112502733150.
The previous prime is 13112502733097. The next prime is 13112502733163. The reversal of 13112502733151 is 15133720521131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13112502733151 - 218 = 13112502471007 is a prime.
It is a super-2 number, since 2×131125027331512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112502733051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556251366575 + 6556251366576.
It is an arithmetic number, because the mean of its divisors is an integer number (6556251366576).
Almost surely, 213112502733151 is an apocalyptic number.
13112502733151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112502733151 is an equidigital number, since it uses as much as digits as its factorization.
13112502733151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18900, while the sum is 35.
The spelling of 13112502733151 in words is "thirteen trillion, one hundred twelve billion, five hundred two million, seven hundred thirty-three thousand, one hundred fifty-one".
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