Base | Representation |
---|---|
bin | 111101000011110101… |
… | …1001101000001000000 |
3 | 110112110100022210212120 |
4 | 1322013223031001000 |
5 | 4122021032043134 |
6 | 140123233324240 |
7 | 12321256251444 |
oct | 1720753150100 |
9 | 415410283776 |
10 | 131125268544 |
11 | 50678883036 |
12 | 214b5706680 |
13 | c4990619ca |
14 | 64bcb04824 |
15 | 3626a3b649 |
hex | 1e87acd040 |
131125268544 has 56 divisors (see below), whose sum is σ = 347266869600. Its totient is φ = 43666689024.
The previous prime is 131125268543. The next prime is 131125268551. The reversal of 131125268544 is 445862521131.
It is a super-2 number, since 2×1311252685442 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131125268496 and 131125268505.
It is not an unprimeable number, because it can be changed into a prime (131125268543) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 124114 + ... + 526929.
It is an arithmetic number, because the mean of its divisors is an integer number (6201194100).
Almost surely, 2131125268544 is an apocalyptic number.
It is an amenable number.
131125268544 is an abundant number, since it is smaller than the sum of its proper divisors (216141601056).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131125268544 is a wasteful number, since it uses less digits than its factorization.
131125268544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 652107 (or 652097 counting only the distinct ones).
The product of its digits is 230400, while the sum is 42.
Adding to 131125268544 its reverse (445862521131), we get a palindrome (576987789675).
The spelling of 131125268544 in words is "one hundred thirty-one billion, one hundred twenty-five million, two hundred sixty-eight thousand, five hundred forty-four".
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