Base | Representation |
---|---|
bin | 11000011011001100… |
… | …01110001110001111 |
3 | 1020211212110201012021 |
4 | 30031212032032033 |
5 | 203323413303143 |
6 | 10005105351011 |
7 | 642644606551 |
oct | 141546161617 |
9 | 36755421167 |
10 | 13113025423 |
11 | 5619a630a3 |
12 | 265b638467 |
13 | 130c926154 |
14 | 8c578b4d1 |
15 | 51b32aced |
hex | 30d98e38f |
13113025423 has 2 divisors, whose sum is σ = 13113025424. Its totient is φ = 13113025422.
The previous prime is 13113025411. The next prime is 13113025447. The reversal of 13113025423 is 32452031131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13113025423 - 213 = 13113017231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13113025403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556512711 + 6556512712.
It is an arithmetic number, because the mean of its divisors is an integer number (6556512712).
Almost surely, 213113025423 is an apocalyptic number.
13113025423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113025423 is an equidigital number, since it uses as much as digits as its factorization.
13113025423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 13113025423 its reverse (32452031131), we get a palindrome (45565056554).
The spelling of 13113025423 in words is "thirteen billion, one hundred thirteen million, twenty-five thousand, four hundred twenty-three".
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