Base | Representation |
---|---|
bin | 11101110100001100100111… |
… | …101010101101110011000000 |
3 | 122012021221020220111101021200 |
4 | 131310030213222231303000 |
5 | 114141414334334220412 |
6 | 1142520233403221200 |
7 | 36422565242321544 |
oct | 3564144752556300 |
9 | 565257226441250 |
10 | 131130312023232 |
11 | 38867064638995 |
12 | 12859b24217800 |
13 | 58226c6272a82 |
14 | 2454a532d3a24 |
15 | 10260012599dc |
hex | 774327aadcc0 |
131130312023232 has 84 divisors (see below), whose sum is σ = 375953065745400. Its totient is φ = 43699439619072.
The previous prime is 131130312023213. The next prime is 131130312023299. The reversal of 131130312023232 is 232320213031131.
131130312023232 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 303 + 120 + 2 + 3 + 232 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 131130312023196 and 131130312023205.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 25408773 + ... + 30130820.
Almost surely, 2131130312023232 is an apocalyptic number.
131130312023232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131130312023232 is an abundant number, since it is smaller than the sum of its proper divisors (244822753722168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131130312023232 is a wasteful number, since it uses less digits than its factorization.
131130312023232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55543710 (or 55543697 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 131130312023232 its reverse (232320213031131), we get a palindrome (363450525054363).
The spelling of 131130312023232 in words is "one hundred thirty-one trillion, one hundred thirty billion, three hundred twelve million, twenty-three thousand, two hundred thirty-two".
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