Base | Representation |
---|---|
bin | 11101110100001101010010… |
… | …101001011111000101001100 |
3 | 122012022000010011100221121010 |
4 | 131310031102221133011030 |
5 | 114141422323434333400 |
6 | 1142520433123005220 |
7 | 36422622146463645 |
oct | 3564152251370514 |
9 | 565260104327533 |
10 | 131131033121100 |
11 | 388673a4688441 |
12 | 1285a0a5809810 |
13 | 58227ac78b1bc |
14 | 2454ac0da06cc |
15 | 10260446e8450 |
hex | 774352a5f14c |
131131033121100 has 72 divisors (see below), whose sum is σ = 387478252804608. Its totient is φ = 34224269633600.
The previous prime is 131131033121093. The next prime is 131131033121177. The reversal of 131131033121100 is 1121330131131.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4650022536 + ... + 4650050735.
It is an arithmetic number, because the mean of its divisors is an integer number (5381642400064).
Almost surely, 2131131033121100 is an apocalyptic number.
131131033121100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131131033121100 is an abundant number, since it is smaller than the sum of its proper divisors (256347219683508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131131033121100 is a wasteful number, since it uses less digits than its factorization.
131131033121100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9300073335 (or 9300073328 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 131131033121100 its reverse (1121330131131), we get a palindrome (132252363252231).
The spelling of 131131033121100 in words is "one hundred thirty-one trillion, one hundred thirty-one billion, thirty-three million, one hundred twenty-one thousand, one hundred".
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