Base | Representation |
---|---|
bin | 10011000101010000010… |
… | …110111010101110111100 |
3 | 11122100201200011002020001 |
4 | 103011100112322232330 |
5 | 132441032140212200 |
6 | 2442224201004044 |
7 | 163511364243652 |
oct | 23052026725674 |
9 | 4570650132201 |
10 | 1311313210300 |
11 | 466141137575 |
12 | 192184183624 |
13 | 9686bb96712 |
14 | 47679caadd2 |
15 | 2419c23276a |
hex | 131505babbc |
1311313210300 has 18 divisors (see below), whose sum is σ = 2845549666568. Its totient is φ = 524525284080.
The previous prime is 1311313210289. The next prime is 1311313210301. The reversal of 1311313210300 is 30123131131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311313210301) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6556565952 + ... + 6556566151.
Almost surely, 21311313210300 is an apocalyptic number.
1311313210300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1311313210300 is an abundant number, since it is smaller than the sum of its proper divisors (1534236456268).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311313210300 is a wasteful number, since it uses less digits than its factorization.
1311313210300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13113132117 (or 13113132110 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1311313210300 its reverse (30123131131), we get a palindrome (1341436341431).
The spelling of 1311313210300 in words is "one trillion, three hundred eleven billion, three hundred thirteen million, two hundred ten thousand, three hundred".
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