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1311313210300 = 225213113132103
BaseRepresentation
bin10011000101010000010…
…110111010101110111100
311122100201200011002020001
4103011100112322232330
5132441032140212200
62442224201004044
7163511364243652
oct23052026725674
94570650132201
101311313210300
11466141137575
12192184183624
139686bb96712
1447679caadd2
152419c23276a
hex131505babbc

1311313210300 has 18 divisors (see below), whose sum is σ = 2845549666568. Its totient is φ = 524525284080.

The previous prime is 1311313210289. The next prime is 1311313210301. The reversal of 1311313210300 is 30123131131.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311313210301) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6556565952 + ... + 6556566151.

Almost surely, 21311313210300 is an apocalyptic number.

1311313210300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1311313210300 is an abundant number, since it is smaller than the sum of its proper divisors (1534236456268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311313210300 is a wasteful number, since it uses less digits than its factorization.

1311313210300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13113132117 (or 13113132110 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1311313210300 its reverse (30123131131), we get a palindrome (1341436341431).

The spelling of 1311313210300 in words is "one trillion, three hundred eleven billion, three hundred thirteen million, two hundred ten thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 13113132103 26226264206 52452528412 65565660515 131131321030 262262642060 327828302575 655656605150 1311313210300