1311313210301 has 2 divisors, whose sum is σ = 1311313210302. Its totient is φ = 1311313210300.

The previous prime is 1311313210289. The next prime is 1311313210313. The reversal of 1311313210301 is 1030123131131.

It is a balanced prime because it is at equal distance from previous prime (1311313210289) and next prime (1311313210313).

It can be written as a sum of positive squares in only one way, i.e., 973525582276 + 337787628025 = 986674^2 + 581195^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311313210301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311313210331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655656605150 + 655656605151.

It is an arithmetic number, because the mean of its divisors is an integer number (655656605151).

Almost surely, 2^{1311313210301} is an apocalyptic number.

It is an amenable number.

1311313210301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311313210301 is an equidigital number, since it uses as much as digits as its factorization.

1311313210301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1311313210301 its reverse (1030123131131), we get a palindrome (2341436341432).

The spelling of 1311313210301 in words is "one trillion, three hundred eleven billion, three hundred thirteen million, two hundred ten thousand, three hundred one".