1311334331101 has 2 divisors, whose sum is σ = 1311334331102. Its totient is φ = 1311334331100.

The previous prime is 1311334331063. The next prime is 1311334331107. The reversal of 1311334331101 is 1011334331131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 796111847001 + 515222484100 = 892251^2 + 717790^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311334331101 - 2³⁹ = 761578517213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311334331107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655667165550 + 655667165551.

It is an arithmetic number, because the mean of its divisors is an integer number (655667165551).

Almost surely, 2^{1311334331101} is an apocalyptic number.

It is an amenable number.

1311334331101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311334331101 is an equidigital number, since it uses as much as digits as its factorization.

1311334331101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 1311334331101 its reverse (1011334331131), we get a palindrome (2322668662232).

The spelling of 1311334331101 in words is "one trillion, three hundred eleven billion, three hundred thirty-four million, three hundred thirty-one thousand, one hundred one".