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1311334331132 = 2271767308313337
BaseRepresentation
bin10011000101010001100…
…111011111001011111100
311122100210010220010120002
4103011101213133023330
5132441103042044012
62442230233413432
7163512041621510
oct23052147371374
94570703803502
101311334331132
11466152052a01
1219218b26a278
1396873380057
144767ca08140
152419e0057c2
hex131519df2fc

1311334331132 has 96 divisors (see below), whose sum is σ = 2819515765248. Its totient is φ = 520838866944.

The previous prime is 1311334331117. The next prime is 1311334331159. The reversal of 1311334331132 is 2311334331131.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 1311334331095 and 1311334331104.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 98316368 + ... + 98329704.

It is an arithmetic number, because the mean of its divisors is an integer number (29369955888).

Almost surely, 21311334331132 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311334331132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1409757882624).

1311334331132 is an abundant number, since it is smaller than the sum of its proper divisors (1508181434116).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311334331132 is a wasteful number, since it uses less digits than its factorization.

1311334331132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16515 (or 16513 counting only the distinct ones).

The product of its digits is 5832, while the sum is 29.

Adding to 1311334331132 its reverse (2311334331131), we get a palindrome (3622668662263).

Subtracting 1311334331132 from its reverse (2311334331131), we obtain a palindrome (999999999999).

The spelling of 1311334331132 in words is "one trillion, three hundred eleven billion, three hundred thirty-four million, three hundred thirty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 7 14 17 28 34 67 68 119 134 238 268 469 476 938 1139 1876 2278 3083 4556 6166 7973 12332 13337 15946 21581 26674 31892 43162 52411 53348 86324 93359 104822 186718 206561 209644 226729 366877 373436 413122 453458 733754 826244 893579 906916 1445927 1467508 1587103 1787158 2891854 3174206 3511537 3574316 5783708 6255053 6348412 7023074 12510106 14046148 15190843 24580759 25020212 30381686 41117971 49161518 60763372 82235942 98323036 106335901 164471884 212671802 287825797 425343604 575651594 699005507 1151303188 1398011014 2754904057 2796022028 4893038549 5509808114 9786077098 11019616228 19284328399 19572154196 38568656798 46833368969 77137313596 93666737938 187333475876 327833582783 655667165566 1311334331132