131141425552440 has 128 divisors (see below), whose sum is σ = 401201760476160. Its totient is φ = 34285452125184.

The previous prime is 131141425552369. The next prime is 131141425552441. The reversal of 131141425552440 is 44255524141131.

It is a super-3 number, since 3×131141425552440³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131141425552392 and 131141425552401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131141425552441) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 43358884 + ... + 46284723.

It is an arithmetic number, because the mean of its divisors is an integer number (3134388753720).

Almost surely, 2^{131141425552440} is an apocalyptic number.

131141425552440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131141425552440 is an abundant number, since it is smaller than the sum of its proper divisors (270060334923720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141425552440 is a wasteful number, since it uses less digits than its factorization.

131141425552440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89643861 (or 89643857 counting only the distinct ones).

The product of its (nonzero) digits is 384000, while the sum is 42.

Adding to 131141425552440 its reverse (44255524141131), we get a palindrome (175396949693571).

The spelling of 131141425552440 in words is "one hundred thirty-one trillion, one hundred forty-one billion, four hundred twenty-five million, five hundred fifty-two thousand, four hundred forty".