131142131223444 has 36 divisors (see below), whose sum is σ = 361634361859680. Its totient is φ = 39740039764560.

The previous prime is 131142131223421. The next prime is 131142131223451. The reversal of 131142131223444 is 444322131241131.

131142131223444 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 421 + 3 + 1 + 223 + 4 + 4 + 4 = 666.

It is a tau number, because it is divible by the number of its divisors (36).

It is a super-2 number, since 2×131142131223444² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 131142131223399 and 131142131223408.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 165583498624 + ... + 165583499415.

Almost surely, 2^{131142131223444} is an apocalyptic number.

It is an amenable number.

131142131223444 is an abundant number, since it is smaller than the sum of its proper divisors (230492230636236).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131142131223444 is a wasteful number, since it uses less digits than its factorization.

131142131223444 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 331166998060 (or 331166998055 counting only the distinct ones).

The product of its digits is 55296, while the sum is 36.

Adding to 131142131223444 its reverse (444322131241131), we get a palindrome (575464262464575).

The spelling of 131142131223444 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred thirty-one million, two hundred twenty-three thousand, four hundred forty-four".