131143323433200 has 240 divisors, whose sum is σ = 452518298225280. Its totient is φ = 32273765821440.

The previous prime is 131143323433097. The next prime is 131143323433219. The reversal of 131143323433200 is 2334323341131.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (240).

It is a super-3 number, since 3×131143323433200³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 64820119 + ... + 66812681.

It is an arithmetic number, because the mean of its divisors is an integer number (1885492909272).

Almost surely, 2^{131143323433200} is an apocalyptic number.

131143323433200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131143323433200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (226259149112640).

131143323433200 is an abundant number, since it is smaller than the sum of its proper divisors (321374974792080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131143323433200 is a wasteful number, since it uses less digits than its factorization.

131143323433200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1996816 (or 1996805 counting only the distinct ones).

The product of its (nonzero) digits is 46656, while the sum is 33.

Adding to 131143323433200 its reverse (2334323341131), we get a palindrome (133477646774331).

The spelling of 131143323433200 in words is "one hundred thirty-one trillion, one hundred forty-three billion, three hundred twenty-three million, four hundred thirty-three thousand, two hundred".