1311454342040 has 32 divisors (see below), whose sum is σ = 2956782033360. Its totient is φ = 523513334400.

The previous prime is 1311454342027. The next prime is 1311454342073. The reversal of 1311454342040 is 402434541131.

It is a super-2 number, since 2×1311454342040² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311454341988 and 1311454342006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33367691 + ... + 33406970.

Almost surely, 2^{1311454342040} is an apocalyptic number.

1311454342040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1311454342040 is an abundant number, since it is smaller than the sum of its proper divisors (1645327691320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311454342040 is a wasteful number, since it uses less digits than its factorization.

1311454342040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66775163 (or 66775159 counting only the distinct ones).

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 1311454342040 its reverse (402434541131), we get a palindrome (1713888883171).

The spelling of 1311454342040 in words is "one trillion, three hundred eleven billion, four hundred fifty-four million, three hundred forty-two thousand, forty".