1311505440100 has 72 divisors (see below), whose sum is σ = 2948944255488. Its totient is φ = 505748870400.

The previous prime is 1311505440031. The next prime is 1311505440101. The reversal of 1311505440100 is 10445051131.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (1311505440101) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10992 + ... + 1619608.

It is an arithmetic number, because the mean of its divisors is an integer number (40957559104).

Almost surely, 2^{1311505440100} is an apocalyptic number.

1311505440100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311505440100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1474472127744).

1311505440100 is an abundant number, since it is smaller than the sum of its proper divisors (1637438815388).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311505440100 is a wasteful number, since it uses less digits than its factorization.

1311505440100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1608925 (or 1608918 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 25.

The spelling of 1311505440100 in words is "one trillion, three hundred eleven billion, five hundred five million, four hundred forty thousand, one hundred".