Base | Representation |
---|---|
bin | 11101110101001101100100… |
… | …110001000101100111110101 |
3 | 122012112121021112011222201221 |
4 | 131311031210301011213311 |
5 | 114144040203441034342 |
6 | 1143012250211150341 |
7 | 36430614465300514 |
oct | 3565154461054765 |
9 | 565477245158657 |
10 | 131200056580597 |
11 | 388936a461a144 |
12 | 1286b5495a53b1 |
13 | 582915c7c0624 |
14 | 245818c01467b |
15 | 1027c3420da67 |
hex | 775364c459f5 |
131200056580597 has 2 divisors, whose sum is σ = 131200056580598. Its totient is φ = 131200056580596.
The previous prime is 131200056580591. The next prime is 131200056580603. The reversal of 131200056580597 is 795085650002131.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (131200056580591) and next prime (131200056580603).
It can be written as a sum of positive squares in only one way, i.e., 126169483085361 + 5030573495236 = 11232519^2 + 2242894^2 .
It is a cyclic number.
It is not a de Polignac number, because 131200056580597 - 243 = 122403963558389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131200056580591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65600028290298 + 65600028290299.
It is an arithmetic number, because the mean of its divisors is an integer number (65600028290299).
Almost surely, 2131200056580597 is an apocalyptic number.
It is an amenable number.
131200056580597 is a deficient number, since it is larger than the sum of its proper divisors (1).
131200056580597 is an equidigital number, since it uses as much as digits as its factorization.
131200056580597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268000, while the sum is 52.
The spelling of 131200056580597 in words is "one hundred thirty-one trillion, two hundred billion, fifty-six million, five hundred eighty thousand, five hundred ninety-seven".
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