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131203434044144 = 24711272179391273
BaseRepresentation
bin11101110101010000101110…
…000101000101101011110000
3122012112220222220110220201102
4131311100232011011223300
5114144114113103403034
61143014005302023532
736431064256253150
oct3565205605055360
9565486886426642
10131203434044144
1138895078062530
1212870130717ba8
13582957a455677
1424583cc7d6760
151027d809b397e
hex77542e145af0

131203434044144 has 80 divisors (see below), whose sum is σ = 316934944984320. Its totient is φ = 51117902599680.

The previous prime is 131203434044117. The next prime is 131203434044149. The reversal of 131203434044144 is 441440434302131.

It is a happy number.

It is a super-2 number, since 2×1312034340441442 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131203434044098 and 131203434044107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131203434044149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 335128892 + ... + 335520164.

It is an arithmetic number, because the mean of its divisors is an integer number (3961686812304).

Almost surely, 2131203434044144 is an apocalyptic number.

131203434044144 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

131203434044144 is an abundant number, since it is smaller than the sum of its proper divisors (185731510940176).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131203434044144 is a wasteful number, since it uses less digits than its factorization.

131203434044144 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 663478 (or 663472 counting only the distinct ones).

The product of its (nonzero) digits is 221184, while the sum is 38.

Adding to 131203434044144 its reverse (441440434302131), we get a palindrome (572643868346275).

The spelling of 131203434044144 in words is "one hundred thirty-one trillion, two hundred three billion, four hundred thirty-four million, forty-four thousand, one hundred forty-four".

Divisors: 1 2 4 7 8 11 14 16 22 28 44 56 77 88 112 154 176 308 616 1232 272179 391273 544358 782546 1088716 1565092 1905253 2177432 2738911 2993969 3130184 3810506 4304003 4354864 5477822 5987938 6260368 7621012 8608006 10955644 11975876 15242024 17216012 20957783 21911288 23951752 30128021 30484048 34432024 41915566 43822576 47903504 60256042 68864048 83831132 120512084 167662264 241024168 335324528 482048336 106496293867 212992587734 425985175468 745474057069 851970350936 1171459232537 1490948114138 1703940701872 2342918465074 2981896228276 4685836930148 5963792456552 8200214627759 9371673860296 11927584913104 16400429255518 18743347720592 32800858511036 65601717022072 131203434044144