131203500344040 has 64 divisors (see below), whose sum is σ = 406307613980160. Its totient is φ = 33858967829760.

The previous prime is 131203500344027. The next prime is 131203500344047. The reversal of 131203500344040 is 40443005302131.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 131203500343989 and 131203500344007.

It is not an unprimeable number, because it can be changed into a prime (131203500344047) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17634875359 + ... + 17634882798.

It is an arithmetic number, because the mean of its divisors is an integer number (6348556468440).

Almost surely, 2^{131203500344040} is an apocalyptic number.

131203500344040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131203500344040 is an abundant number, since it is smaller than the sum of its proper divisors (275104113636120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131203500344040 is a wasteful number, since it uses less digits than its factorization.

131203500344040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35269758202 (or 35269758198 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 131203500344040 its reverse (40443005302131), we get a palindrome (171646505646171).

The spelling of 131203500344040 in words is "one hundred thirty-one trillion, two hundred three billion, five hundred million, three hundred forty-four thousand, forty".