131211034501410 has 96 divisors (see below), whose sum is σ = 341947638789120. Its totient is φ = 34907693192064.

The previous prime is 131211034501373. The next prime is 131211034501411. The reversal of 131211034501410 is 14105430112131.

131211034501410 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 110 + 3 + 4 + 501 + 41 + 0 = 666.

131211034501410 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×131211034501410³ (a number of 43 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (131211034501411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 231276871 + ... + 231843509.

It is an arithmetic number, because the mean of its divisors is an integer number (3561954570720).

Almost surely, 2^{131211034501410} is an apocalyptic number.

131211034501410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131211034501410 is an abundant number, since it is smaller than the sum of its proper divisors (210736604287710).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131211034501410 is a wasteful number, since it uses less digits than its factorization.

131211034501410 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 572672 (or 572669 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 27.

Adding to 131211034501410 its reverse (14105430112131), we get a palindrome (145316464613541).

The spelling of 131211034501410 in words is "one hundred thirty-one trillion, two hundred eleven billion, thirty-four million, five hundred one thousand, four hundred ten".