131211440300040 has 64 divisors (see below), whose sum is σ = 395673877036800. Its totient is φ = 34808423534592.

The previous prime is 131211440300021. The next prime is 131211440300053. The reversal of 131211440300040 is 40003044112131.

It is a super-2 number, since 2×131211440300040² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2832693600 + ... + 2832739919.

It is an arithmetic number, because the mean of its divisors is an integer number (6182404328700).

Almost surely, 2^{131211440300040} is an apocalyptic number.

131211440300040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131211440300040 is an abundant number, since it is smaller than the sum of its proper divisors (264462436736760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131211440300040 is a wasteful number, since it uses less digits than its factorization.

131211440300040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5665433726 (or 5665433722 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 131211440300040 its reverse (40003044112131), we get a palindrome (171214484412171).

The spelling of 131211440300040 in words is "one hundred thirty-one trillion, two hundred eleven billion, four hundred forty million, three hundred thousand, forty".