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131212011157 is a prime number
BaseRepresentation
bin111101000110011011…
…0000110011010010101
3110112200101112210100221
41322030312012122111
54122210233324112
6140140012434341
712323361456403
oct1721466063225
9415611483327
10131212011157
115071283a047
122151a7789b1
13c4b10130b6
1464ca444473
15362e472e07
hex1e8cd86695

131212011157 has 2 divisors, whose sum is σ = 131212011158. Its totient is φ = 131212011156.

The previous prime is 131212011131. The next prime is 131212011199. The reversal of 131212011157 is 751110212131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123257868561 + 7954142596 = 351081^2 + 89186^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131212011157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131212012157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606005578 + 65606005579.

It is an arithmetic number, because the mean of its divisors is an integer number (65606005579).

Almost surely, 2131212011157 is an apocalyptic number.

It is an amenable number.

131212011157 is a deficient number, since it is larger than the sum of its proper divisors (1).

131212011157 is an equidigital number, since it uses as much as digits as its factorization.

131212011157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 420, while the sum is 25.

Adding to 131212011157 its reverse (751110212131), we get a palindrome (882322223288).

The spelling of 131212011157 in words is "one hundred thirty-one billion, two hundred twelve million, eleven thousand, one hundred fifty-seven".