Base | Representation |
---|---|
bin | 11101110101011001000111… |
… | …001000100111100000110010 |
3 | 122012120210020211221001221100 |
4 | 131311121013020213200302 |
5 | 114144241041222143010 |
6 | 1143022055331505230 |
7 | 36431533455412155 |
oct | 3565310710474062 |
9 | 565523224831840 |
10 | 131212444334130 |
11 | 38898981141785 |
12 | 12871a26158216 |
13 | 582a3850994c3 |
14 | 2458a05329c9c |
15 | 102820ba242c0 |
hex | 775647227832 |
131212444334130 has 96 divisors (see below), whose sum is σ = 343645808688000. Its totient is φ = 34734303668736.
The previous prime is 131212444334129. The next prime is 131212444334141. The reversal of 131212444334130 is 31433444212131.
131212444334130 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 1 + 244 + 43 + 341 + 30 = 666.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 110108347 + ... + 111293633.
It is an arithmetic number, because the mean of its divisors is an integer number (3579643840500).
Almost surely, 2131212444334130 is an apocalyptic number.
131212444334130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 131212444334130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (171822904344000).
131212444334130 is an abundant number, since it is smaller than the sum of its proper divisors (212433364353870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131212444334130 is a wasteful number, since it uses less digits than its factorization.
131212444334130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1194288 (or 1194285 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 36.
Adding to 131212444334130 its reverse (31433444212131), we get a palindrome (162645888546261).
The spelling of 131212444334130 in words is "one hundred thirty-one trillion, two hundred twelve billion, four hundred forty-four million, three hundred thirty-four thousand, one hundred thirty".
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