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131213223133 is a prime number
BaseRepresentation
bin111101000110011101…
…0101110010011011101
3110112200110211100212221
41322030322232103131
54122211041120013
6140140054425341
712323404665016
oct1721472562335
9415613740787
10131213223133
1150713497683
122151b062251
13c4b1348945
1464ca67c00d
15362e61208d
hex1e8ceae4dd

131213223133 has 2 divisors, whose sum is σ = 131213223134. Its totient is φ = 131213223132.

The previous prime is 131213223131. The next prime is 131213223157. The reversal of 131213223133 is 331322312131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110252553849 + 20960669284 = 332043^2 + 144778^2 .

It is a cyclic number.

It is not a de Polignac number, because 131213223133 - 21 = 131213223131 is a prime.

Together with 131213223131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 131213223098 and 131213223107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131213223131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65606611566 + 65606611567.

It is an arithmetic number, because the mean of its divisors is an integer number (65606611567).

Almost surely, 2131213223133 is an apocalyptic number.

It is an amenable number.

131213223133 is a deficient number, since it is larger than the sum of its proper divisors (1).

131213223133 is an equidigital number, since it uses as much as digits as its factorization.

131213223133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1944, while the sum is 25.

Adding to 131213223133 its reverse (331322312131), we get a palindrome (462535535264).

The spelling of 131213223133 in words is "one hundred thirty-one billion, two hundred thirteen million, two hundred twenty-three thousand, one hundred thirty-three".