1312141034129 has 2 divisors, whose sum is σ = 1312141034130. Its totient is φ = 1312141034128.

The previous prime is 1312141034119. The next prime is 1312141034131. The reversal of 1312141034129 is 9214301412131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1231611648400 + 80529385729 = 1109780^2 + 283777^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312141034129 - 2⁸ = 1312141033873 is a prime.

Together with 1312141034131, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1312141034095 and 1312141034104.

It is not a weakly prime, because it can be changed into another prime (1312141034119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656070517064 + 656070517065.

It is an arithmetic number, because the mean of its divisors is an integer number (656070517065).

Almost surely, 2^{1312141034129} is an apocalyptic number.

It is an amenable number.

1312141034129 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312141034129 is an equidigital number, since it uses as much as digits as its factorization.

1312141034129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 1312141034129 in words is "one trillion, three hundred twelve billion, one hundred forty-one million, thirty-four thousand, one hundred twenty-nine".