Base | Representation |
---|---|
bin | 11101110101100010010100… |
… | …100011101110100101011010 |
3 | 122012121201210000121120210101 |
4 | 131311202110203232211122 |
5 | 114144421314301034320 |
6 | 1143030412505010014 |
7 | 36432333513515560 |
oct | 3565422443564532 |
9 | 565551700546711 |
10 | 131222333221210 |
11 | 388a2096164a30 |
12 | 12873925a8390a |
13 | 582b29ca51b8a |
14 | 24592a2807a30 |
15 | 10285d9c84c0a |
hex | 7758948ee95a |
131222333221210 has 128 divisors (see below), whose sum is σ = 310009780776960. Its totient is φ = 38744400038400.
The previous prime is 131222333221163. The next prime is 131222333221241. The reversal of 131222333221210 is 12122333222131.
It is a super-2 number, since 2×1312223332212102 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 168250950 + ... + 169029070.
It is an arithmetic number, because the mean of its divisors is an integer number (2421951412320).
Almost surely, 2131222333221210 is an apocalyptic number.
131222333221210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131222333221210 is an abundant number, since it is smaller than the sum of its proper divisors (178787447555750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131222333221210 is a wasteful number, since it uses less digits than its factorization.
131222333221210 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 789692.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 131222333221210 its reverse (12122333222131), we get a palindrome (143344666443341).
The spelling of 131222333221210 in words is "one hundred thirty-one trillion, two hundred twenty-two billion, three hundred thirty-three million, two hundred twenty-one thousand, two hundred ten".
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