Base | Representation |
---|---|
bin | 1011111011110100110011… |
… | …0010101101011100101010 |
3 | 1201110111020120000011012212 |
4 | 2332331030302231130222 |
5 | 3204444200320413200 |
6 | 43524204205405122 |
7 | 2523030431642261 |
oct | 276751462553452 |
9 | 51414216004185 |
10 | 13122413451050 |
11 | 41aa203324362 |
12 | 157b2658697a2 |
13 | 742590b8aa17 |
14 | 3351b1acd5d8 |
15 | 17b52646e035 |
hex | bef4ccad72a |
13122413451050 has 24 divisors (see below), whose sum is σ = 24408572834316. Its totient is φ = 5248775312640.
The previous prime is 13122413451031. The next prime is 13122413451061. The reversal of 13122413451050 is 5015431422131.
It can be written as a sum of positive squares in 6 ways, for example, as 8071045921 + 13114342405129 = 89839^2 + 3621373^2 .
It is a super-2 number, since 2×131224134510502 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13122413450998 and 13122413451016.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3352997 + ... + 6122696.
Almost surely, 213122413451050 is an apocalyptic number.
13122413451050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13122413451050 is a deficient number, since it is larger than the sum of its proper divisors (11286159383266).
13122413451050 is a wasteful number, since it uses less digits than its factorization.
13122413451050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9503402 (or 9503397 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 13122413451050 its reverse (5015431422131), we get a palindrome (18137844873181).
The spelling of 13122413451050 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, four hundred fifty-one thousand, fifty".
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