Base | Representation |
---|---|
bin | 111101000110110010… |
… | …0010110010111000111 |
3 | 110112201020100202022021 |
4 | 1322031210112113013 |
5 | 4122221334310421 |
6 | 140141124344011 |
7 | 12323566513246 |
oct | 1721544262707 |
9 | 415636322267 |
10 | 131224135111 |
11 | 5071966aa43 |
12 | 21522845007 |
13 | c4b3699634 |
14 | 64cbcbc95d |
15 | 363056a341 |
hex | 1e8d9165c7 |
131224135111 has 2 divisors, whose sum is σ = 131224135112. Its totient is φ = 131224135110.
The previous prime is 131224135109. The next prime is 131224135157. The reversal of 131224135111 is 111531422131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131224135111 - 21 = 131224135109 is a prime.
Together with 131224135109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131224115111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65612067555 + 65612067556.
It is an arithmetic number, because the mean of its divisors is an integer number (65612067556).
Almost surely, 2131224135111 is an apocalyptic number.
131224135111 is a deficient number, since it is larger than the sum of its proper divisors (1).
131224135111 is an equidigital number, since it uses as much as digits as its factorization.
131224135111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 720, while the sum is 25.
Adding to 131224135111 its reverse (111531422131), we get a palindrome (242755557242).
The spelling of 131224135111 in words is "one hundred thirty-one billion, two hundred twenty-four million, one hundred thirty-five thousand, one hundred eleven".
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