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13122413915231 is a prime number
BaseRepresentation
bin1011111011110100110011…
…0100011110110001011111
31201110111020120212201221202
42332331030310132301133
53204444200430241411
643524204223350115
72523030435614465
oct276751464366137
951414216781852
1013122413915231
1141aa203611085
12157b265a5233b
13742590cc109a
143351b1bb0835
1517b52651183b
hexbef4cd1ec5f

13122413915231 has 2 divisors, whose sum is σ = 13122413915232. Its totient is φ = 13122413915230.

The previous prime is 13122413915213. The next prime is 13122413915263. The reversal of 13122413915231 is 13251931422131.

Together with previous prime (13122413915213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13122413915231 is a prime.

It is a super-2 number, since 2×131224139152312 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13122413515231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561206957615 + 6561206957616.

It is an arithmetic number, because the mean of its divisors is an integer number (6561206957616).

Almost surely, 213122413915231 is an apocalyptic number.

13122413915231 is a deficient number, since it is larger than the sum of its proper divisors (1).

13122413915231 is an equidigital number, since it uses as much as digits as its factorization.

13122413915231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 38880, while the sum is 38.

The spelling of 13122413915231 in words is "thirteen trillion, one hundred twenty-two billion, four hundred thirteen million, nine hundred fifteen thousand, two hundred thirty-one".