Base | Representation |
---|---|
bin | 10011000110001011010… |
… | …100000100100111101111 |
3 | 11122110021121100001210202 |
4 | 103012023110010213233 |
5 | 133000043343220421 |
6 | 2442510253024115 |
7 | 163545034450016 |
oct | 23061324044757 |
9 | 4573247301722 |
10 | 1312302320111 |
11 | 4665a94a23a2 |
12 | 1923bb48503b |
13 | 96998a8cab3 |
14 | 477313c1a7d |
15 | 24208eb210b |
hex | 1318b5049ef |
1312302320111 has 2 divisors, whose sum is σ = 1312302320112. Its totient is φ = 1312302320110.
The previous prime is 1312302320107. The next prime is 1312302320113. The reversal of 1312302320111 is 1110232032131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1312302320111 - 22 = 1312302320107 is a prime.
It is a Sophie Germain prime.
Together with 1312302320113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312302320113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656151160055 + 656151160056.
It is an arithmetic number, because the mean of its divisors is an integer number (656151160056).
Almost surely, 21312302320111 is an apocalyptic number.
1312302320111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312302320111 is an equidigital number, since it uses as much as digits as its factorization.
1312302320111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1312302320111 its reverse (1110232032131), we get a palindrome (2422534352242).
The spelling of 1312302320111 in words is "one trillion, three hundred twelve billion, three hundred two million, three hundred twenty thousand, one hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.062 sec. • engine limits •