Base | Representation |
---|---|
bin | 111101000110111111… |
… | …0100100110011001111 |
3 | 110112201201022000212202 |
4 | 1322031332210303033 |
5 | 4122230114304444 |
6 | 140141531552115 |
7 | 12324012115535 |
oct | 1721576446317 |
9 | 415651260782 |
10 | 131231009999 |
11 | 50722536171 |
12 | 21524bbb63b |
13 | c4b4c3590b |
14 | 64ccb8c155 |
15 | 3630e7734e |
hex | 1e8dfa4ccf |
131231009999 has 2 divisors, whose sum is σ = 131231010000. Its totient is φ = 131231009998.
The previous prime is 131231009983. The next prime is 131231010017. The reversal of 131231009999 is 999900132131.
It is a weak prime.
It is an emirp because it is prime and its reverse (999900132131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131231009999 - 24 = 131231009983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131231009929) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65615504999 + 65615505000.
It is an arithmetic number, because the mean of its divisors is an integer number (65615505000).
Almost surely, 2131231009999 is an apocalyptic number.
131231009999 is a deficient number, since it is larger than the sum of its proper divisors (1).
131231009999 is an equidigital number, since it uses as much as digits as its factorization.
131231009999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 118098, while the sum is 47.
The spelling of 131231009999 in words is "one hundred thirty-one billion, two hundred thirty-one million, nine thousand, nine hundred ninety-nine".
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