Base | Representation |
---|---|
bin | 10011000110001011110… |
… | …110011000001100111101 |
3 | 11122110022020020222000121 |
4 | 103012023312120030331 |
5 | 133000103144010323 |
6 | 2442511213454541 |
7 | 163545204053665 |
oct | 23061366301475 |
9 | 4573266228017 |
10 | 1312311313213 |
11 | 46660358500a |
12 | 1924024a1451 |
13 | 9699a8bb264 |
14 | 477326831a5 |
15 | 24209b8ba5d |
hex | 1318bd9833d |
1312311313213 has 2 divisors, whose sum is σ = 1312311313214. Its totient is φ = 1312311313212.
The previous prime is 1312311313199. The next prime is 1312311313259. The reversal of 1312311313213 is 3123131132131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1254460480729 + 57850832484 = 1120027^2 + 240522^2 .
It is a cyclic number.
It is not a de Polignac number, because 1312311313213 - 29 = 1312311312701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1312311319213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656155656606 + 656155656607.
It is an arithmetic number, because the mean of its divisors is an integer number (656155656607).
Almost surely, 21312311313213 is an apocalyptic number.
It is an amenable number.
1312311313213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1312311313213 is an equidigital number, since it uses as much as digits as its factorization.
1312311313213 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 972, while the sum is 25.
Adding to 1312311313213 its reverse (3123131132131), we get a palindrome (4435442445344).
The spelling of 1312311313213 in words is "one trillion, three hundred twelve billion, three hundred eleven million, three hundred thirteen thousand, two hundred thirteen".
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