Base | Representation |
---|---|
bin | 1011111011111000010000… |
… | …0101100100010110110111 |
3 | 1201110120122012121201011212 |
4 | 2332332010011210112313 |
5 | 3210003100313011211 |
6 | 43524440225152035 |
7 | 2523062425120043 |
oct | 276760405442667 |
9 | 51416565551155 |
10 | 13123341141431 |
11 | 41aa639a49924 |
12 | 157b48448b61b |
13 | 7426ab12b041 |
14 | 33525cdb7023 |
15 | 17b57cb1a38b |
hex | bef841645b7 |
13123341141431 has 2 divisors, whose sum is σ = 13123341141432. Its totient is φ = 13123341141430.
The previous prime is 13123341141409. The next prime is 13123341141437. The reversal of 13123341141431 is 13414114332131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13123341141431 - 210 = 13123341140407 is a prime.
It is a super-3 number, since 3×131233411414313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13123341141437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6561670570715 + 6561670570716.
It is an arithmetic number, because the mean of its divisors is an integer number (6561670570716).
Almost surely, 213123341141431 is an apocalyptic number.
13123341141431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13123341141431 is an equidigital number, since it uses as much as digits as its factorization.
13123341141431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10368, while the sum is 32.
Adding to 13123341141431 its reverse (13414114332131), we get a palindrome (26537455473562).
The spelling of 13123341141431 in words is "thirteen trillion, one hundred twenty-three billion, three hundred forty-one million, one hundred forty-one thousand, four hundred thirty-one".
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