Base | Representation |
---|---|
bin | 1011111011111100001101… |
… | …1100101000100011100110 |
3 | 1201110200101021212021022001 |
4 | 2332333003130220203212 |
5 | 3210012234430340200 |
6 | 43525133521155514 |
7 | 2523130653425605 |
oct | 276770334504346 |
9 | 51420337767261 |
10 | 13124404152550 |
11 | 4200034a9a909 |
12 | 157b72048bb9a |
13 | 74281a42a8c2 |
14 | 335320247a3c |
15 | 17b5e10e676a |
hex | befc37288e6 |
13124404152550 has 24 divisors (see below), whose sum is σ = 24445343656800. Its totient is φ = 5242460170080.
The previous prime is 13124404152479. The next prime is 13124404152599. The reversal of 13124404152550 is 5525140442131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 182500965 + ... + 182572864.
It is an arithmetic number, because the mean of its divisors is an integer number (1018555985700).
Almost surely, 213124404152550 is an apocalyptic number.
13124404152550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13124404152550 is a deficient number, since it is larger than the sum of its proper divisors (11320939504250).
13124404152550 is a wasteful number, since it uses less digits than its factorization.
13124404152550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 365074560 (or 365074555 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 13124404152550 its reverse (5525140442131), we get a palindrome (18649544594681).
The spelling of 13124404152550 in words is "thirteen trillion, one hundred twenty-four billion, four hundred four million, one hundred fifty-two thousand, five hundred fifty".
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